302 Stroker?

[ADNICK]

Not a real "Ford Guy" but have built a lot of engines, and have a chance to buy a set of ford 302 rods (standard pin and crank size) that are .225 longer than stock.

Is there a crank, rod, piston combo that will produce a stroker with that length rod(s) in a 302 block?

Thanks,
Nick

 

[Broncobowsher]

My mind is a little fuzzy on cold medicine tonight, but is that the 289 rod length?

 

[akafrankcastle]

Maybe a 347? Scat shows 5.400 (.308 difference from stock) for their LG5-5400IBC connecting rods.

289s are .068 longer according to this book I've been reading.

 

[ADNICK]

I can't find a combo

Unless my math is off these rods are 5.315 inches in length and I don't see a combo that uses that length rod???


Thanks,
Nick

 

[fungus]

Unless my math is off these rods are 5.315 inches in length and I don't see a combo that uses that length rod???


Thanks,
Nick

Sounds like a "short stroke" 347 kit setup w/ 5.315 connecting rods. That's what I plan on building for the '68 project. I know it's an option with the SCAT kit.

 

[ADNICK]

Found it! 3.25 crank with the 5.315 rods =331 stroker

 

[StnePny]

Just my $ .02 (I hought )

a 5.400 rod can be use on both a 331 & a 347, but, it depends on the throw (Stroke) of the Crankshaft

a Crank with a 3.250 stroke is a 331 (using a 5.400 Rod )
and
a Crank with a 3.400 stroke is a 347 (using a 5.400 Rod)

( A 5.090 Rod with a 3.000 Stroke Crank is a 306 )

 

[ADNICK]

Thought I mentioned it, but they are .912 pins so it takes the 3.25 stroke with the 5.315 rods which = 331


Nick

 

[StnePny]

You might have said it, but, show me who sell a 5.315 Rod

All I see is 5.400 Rods in the Catalogs ? ?

 

[Broncobowsher]

Coast High Performance sells a "short rod" 347 kit to help solve the 30,000 mile smoker syndrome of the 5.4" rod 347s. I just don't like going that short on the rod ratio. I have always been a long rod fan.

 

[ADNICK]

Many options for .225 rods

I found many vendors that sell the .225 over rods, just did not know what the build was/is...

Now I know....Thanks to all,

Nick